Question 1. Which of the following pairs of linear equations has unique solution, no sol Chapter 3: Pair of Linear Equations in Two Variable Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 1. Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions In case there is a unique solution, find it by using cross multiplication method. (i)x – 3y – 3 = 0 ; 3x – 9y – 2 =0 (ii)2x + y = 5 ; 3x +2y =8 (iii)3x – 5y = 20 ; 6x – 10y =40 (iv)x – 3y – 7 = 0 ;3x – 3y – 15= 0 is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 3 absolutely free. NCERT Solutions for class 10 Maths Chapter 3: Pair of Linear Equations in Two Variable is very essencial for getting good marks in CBSE Board examinations
Question 1. Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions In case there is a unique solution, find it by using cross multiplication method.
(i)x – 3y – 3 = 0 ; 3x – 9y – 2 =0
(ii)2x + y = 5 ; 3x +2y =8
(iii)3x – 5y = 20 ; 6x – 10y =40
(iv)x – 3y – 7 = 0 ;3x – 3y – 15= 0
Answer
(i)
x – 3 y - 3 = 0
3x – 9y - 2 = 0
Compare with
we get
a1 = 1 , b1 = -3 , and c1 = -3
a2 = 3 , b2 = -9 and c2 = -2
Hence
So system has no solutions
(ii)
2x + y = 5
3x + 2y = 8
2x + y - 5 = 0
3x + 2y - 8 = 0
Compare with
we get
a1 = 2 , b1 = 1 , and c1 = -5
a2 = 3 , b2 = 2 and c2 = -8
Hence
So system has unique solutions
Use the formula of cross multiplication
Plug the values in this formula we get
Solve them we get
Answer x = 2 and y = 1
(iii)
3x – 5y = 20
6x – 10 y = 40
3x – 5y - 20 = 0
6x – 10 y - 40 = 0
Compare with
we get
a1 = 3 , b1 = -5 , and c1 = -20
a2 = 6 , b2 = -10 and c2 = -40
Hence
So both lines are coincident and overlap with each other
So it will have infinity or many solutions
(iv)
X – 3y - 7 = 0
3x – 3y -15 = 0
Compare with
we get
a1 = 1 , b1 = -3 , and c1 = -7
a2 = 3 , b2 = -3 and c2 = -15
Hence
So it will have unique solutions
Use the formula of cross multiplication
Plug the values in this formula we get
X = 24/6 = 4
Y = -6/6 = - 1
So our answer is x = 4 and y = - 1
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